[MM-52710] Adding a separator to the channel search string (#24349)
* adding a separator to the search string --------- Co-authored-by: Mattermost Build <build@mattermost.com>
Этот коммит содержится в:
@@ -388,9 +388,10 @@ function makeChannelSearchFilter(channelPrefix: string) {
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const curState = getState();
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const curState = getState();
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const usersInChannels = getUserIdsInChannels(curState);
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const usersInChannels = getUserIdsInChannels(curState);
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const userSearchStrings: RelationOneToOne<UserProfile, string> = {};
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const userSearchStrings: RelationOneToOne<UserProfile, string> = {};
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const SEPARATOR = ';|;';
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return (channel: ChannelItem) => {
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return (channel: ChannelItem) => {
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let searchString = `${channel.display_name}${channel.name}`;
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let searchString = `${channel.display_name}${SEPARATOR}${channel.name}`;
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if (channel.type === Constants.GM_CHANNEL || channel.type === Constants.DM_CHANNEL) {
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if (channel.type === Constants.GM_CHANNEL || channel.type === Constants.DM_CHANNEL) {
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const usersInChannel = usersInChannels[channel.id] || new Set([]);
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const usersInChannel = usersInChannels[channel.id] || new Set([]);
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@@ -412,7 +413,7 @@ function makeChannelSearchFilter(channelPrefix: string) {
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continue;
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continue;
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}
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}
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const {nickname, username} = user;
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const {nickname, username} = user;
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userString = `${nickname}${username}${Utils.getFullName(user)}`;
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userString = [nickname, username, Utils.getFullName(user)].join(SEPARATOR);
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userSearchStrings[userId] = userString;
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userSearchStrings[userId] = userString;
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}
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}
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searchString += userString;
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searchString += userString;
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Ссылка в новой задаче
Block a user